At the sublimation temperature , for the process CO_(2)(s) rarr CO_(2)

1.	At the sublimation temperature , for the process CO_(2)(s) rarr CO_(2)(g),
Answer» `DeltaH , DeltaS` and`DeltaG` are all POSITIVE `DeltaHgt 0,DeltaSgt 0` and `DeltaG LT 0` `DeltaH lt 0, DeltaS gt 0` and `DeltaG lt 0` `DeltaH GT0, DeltaSgt 0` and`DeltaG = 0` Solution :As the PROCESS is in equilibrium,`DeltaG =0`. But `DeltaG=0`only when the TWO factors `DeltaH`and `T DeltaS` oppose each other and equal in magnitude `( DeltaG =DeltaH - T DeltaS)`. Thus, we should have either `DeltaH` and `DeltaS`both `+ve` or both -ve, i.e., `DeltaH gt 0` and`DeltaS gt 0` or `DeltaH lt 0` and `DeltaS lt0`

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