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At the time of marriage, a man was 6 years elder to his wife, but 12 years after the marriage, his age was \(\frac{6}{5}\) times the age of his wife. Then their ages at the time of marriage were1. 25 years and 19 years2. 26 years and 20 years3. 24 years and 18 years4. None of the above |
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Answer» Correct Answer - Option 3 : 24 years and 18 years Given Difference between age of man and woman = 6 years 12 years after the marriage, man's age was 6/5 times the age of his wife Calculation Let the age of wife at the time of marriage be 'x' Then the age of husband at the time of marriage was 'x + 6' After 12 years of marriage, (x + 6) + 12 = (6/5)(x + 12) ⇒ 5(x + 18) = 6(x + 12) ⇒ 5x + 90 = 6x + 72 ⇒ x = 18 So, Age of wife = 18 ∴ Age of husband = 18 + 6 = 24 So, their ages at the time of marriage were 24 years and 18 years |
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