At the two ends of a light string, passing over a stationary, light, smooth pulley, two masses m and 2m are attached. Length of the string on either side of the pulley was the same initially, and the two masses were at a height of 13.08. After the system is released, what will be the velocities of the two masses when the mass m rises by 6.54m? At that moment, if the string snaps suddenly, find the time taken by the masses to reach the ground.

At the two ends of a light string, passing over a stationary, light, s

1.	At the two ends of a light string, passing over a stationary, light, smooth pulley, two masses m and 2m are attached. Length of the string on either side of the pulley was the same initially, and the two masses were at a height of 13.08. After the system is released, what will be the velocities of the two masses when the mass m rises by 6.54m? At that moment, if the string snaps suddenly, find the time taken by the masses to reach the ground.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of each 6.54 m`<a href="https://interviewquestions.tuteehub.com/tag/cdot-407575" style="font-weight:bold;" target="_blank" title="Click to know more about CDOT">CDOT</a> s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) ,t_(1) = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.77 s, t_(2) = -0.67 `s</body></html>