At time t = 0, a material is composed of two radioactive atoms A and B, where NA(0)=2NB(0). The decay constant of both kind of radioactive atoms is λ. However, A disintegrates to B and B disintegrates to C. Which of the following figures represents the evolution of NB(t)/NB(0) with respect to time t ?[NA(0)=No. of atoms at t = 0NB(0)=No. of B atoms at t = 0]

At time t = 0, a material is composed of two radioactive atoms A and B

1.	At time t = 0, a material is composed of two radioactive atoms A and B, where NA(0)=2NB(0). The decay constant of both kind of radioactive atoms is λ. However, A disintegrates to B and B disintegrates to C. Which of the following figures represents the evolution of NB(t)/NB(0) with respect to time t ?[NA(0)=No. of atoms at t = 0NB(0)=No. of B atoms at t = 0]
Answer» At time t = 0, a material is composed of two radioactive atoms A and B, where $N_{A} (0) = 2 N_{B} (0)$ . The decay constant of both kind of radioactive atoms is $λ$ . However, A disintegrates to B and B disintegrates to C. Which of the following figures represents the evolution of $N_{B} (t) / N_{B} (0)$ with respect to time t ? $[N_{A} (0) = No. of atoms at t = 0 N_{B} (0) = No. of B atoms at t = 0]$