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At what distance from the centre of Earth, the value acceleration due to gravity 'g' will be half that of the surface? |
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Answer» SOLUTION :ACCORDING to acceleration due to gravity ` (G.)/g = (R/(R+h))^(2)` `1/2 = (R/(R+h))^(2) RARR 1/(sqrt(2)) = R/(R+h)` `R + h = sqrt(2)R rArr h = (sqrt(2)-1) R ` ` h = 0.414 R ` Hencedistancefrom centre` = R + 0.414 R = 1.414 R ` |
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