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At what rate a sum doubles itself in 8 year 4 months? |
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Answer» Let the principle be P then A = 2P T =8 years 4 months = 8y \(\frac {4}{12}\) y = 8 \(\frac13\) years R = R% say We know that I = \(\frac {PTR}{100}\) Here I = A – P = 2P – P = P ∴ P = \(\frac {P.\frac {25}{3}\times R}{100}\) ∴ R = 100 x \(\frac {3}{25}\) = 12% |
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