At what temperatue will the rms speed of oxygen molecule will be sufficient for esca-ping from the earth ?[v_(e)=11.2 km/s,m=2.76xx10^(-26)Kg and k=1.38xx10^(-23)J/K]

At what temperatue will the rms speed of oxygen molecule will be suffi

1.	At what temperatue will the rms speed of oxygen molecule will be sufficient for esca-ping from the earth ?[v_(e)=11.2 km/s,m=2.76xx10^(-26)Kg and k=1.38xx10^(-23)J/K]
Answer» SOLUTION :The MEAN square VELOCITY of GAS molecule given by `v_(av)=sqrt((2KT)/(m))` For the molecule to just escape from the earth `v_(av)=v_(e)` or `sqrt((2KT)/(m))=v_(e)` `therefore T=(mv_(e)^(2))/(2K)=(5.34xx10^(-26)xx(11.0xx10^(3))^(2))/(2xx1.38xx10^(-23))=2.34xx10^(5)K`