At what temperature, a perfect black body will radiate energy at the rate of 6.48 W//cm^2 . Take, sigma= 5.67 xx 10^(-8) Wm^(-2)K^(-4)

At what temperature, a perfect black body will radiate energy at the r

1.	At what temperature, a perfect black body will radiate energy at the rate of 6.48 W//cm^2 . Take, sigma= 5.67 xx 10^(-8) Wm^(-2)K^(-4)
Answer» Solution :Given `E = 6.48 W cm^(-2) = 6.48 XX 10^4 WM^(-2)` ` sigma = 5.67 xx 10^(-8) Wm^(-2) K^(-4)` Using stefan.s law`E= sigma T^4` ` therefore T= (E/sigma)^(1/4) = ( (6.48 xx 10^4)/(5.67 xx 10^(-8)))^(1/4)` `= 1.033 xx 10^3 = 1033 K`