At what temperature is the "effective" speed of gaseous hydrogen molecules (molecular weight = 2) equal to that of oxygen molecules (molecular weight = 32) at `47^@ C`?

At what temperature is the "effective" speed of gaseous hydrogen molec

1.	At what temperature is the "effective" speed of gaseous hydrogen molecules (molecular weight = 2) equal to that of oxygen molecules (molecular weight = 32) at `47^@ C`?
Answer» Correct Answer - B::C `v_(rms)= sqrt((3 R T)/(M)) prop sqrt((T)/(M))` `v_(rms)` is same. Hence, `((T)/M)_(H 2) = ((T)/(M))_(O 2)` or `T_(H 2) = (M_(H 2)/(M_(O 2))) T_(O2)` `= (2/(32)) (273 + 47)` `= 20 K = - 253^@ C`.

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At what temperature is the "effective" speed of gaseous hydrogen molecules (molecular weight = 2) equal to that of oxygen molecules (molecular weight = 32) at `47^@ C`?

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