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At what temperature the molecule of nitrogen will have same rms velocity as the molecule of oxygen at `127^(@)C` ?A. `77^(@)C`B. `350^(@)C`C. `273^(@)C`D. `457^(@)C` |
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Answer» Correct Answer - D `a=2+|t-2|` For `tle2` `a=2-t+2=4-t` `i.e. dv =(4-t)dt" ""or"" "v=4t-t^(2)//2` At `t = 2, v = 6 m//s` For `t gt 2` `a = 2 + t - 2 = t` `i.e.underset(6)overset(v)intdv=underset(2)overset(t)inttdt" or "v-6=[t^(2)//2]_(2)^(1)" or "v=(t^(2))/(2)+4` At `t=4,v=12m//s` |
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