At what temperature will both the Celsius and Fahrenheit scales read t

1.	At what temperature will both the Celsius and Fahrenheit scales read the same value?
Answer» ℉ = \(\frac{9}{5}\)(ºC) + 32 Or ℉ = \(\big(\)ºC x \(\frac{9}{5}\)\(\big)\)+ 32 t ℃ = (℉ - 32) x \(\frac{5}{9}\) To find the temperature when both are equal, we use an old algebra trick and just set ℉ = ℃ and solve one of the equations. ℃ = \(\big(\)ºC x \(\frac{9}{5}\)\(\big)\)+ 32 Or, ℃ - \(\big(\)℃ x \(\frac{9}{5}\)\(\big)\) = 32 Or, \(-\frac{4}{5}\) x ℃ = 32 Or, ℃ = \(-\frac{32\times5}{4}\) = -40 ℉ = \(\big(^oF\times\frac{9}{5}\big)\)+ 32 Or, ℉ - \(\big(^oF\times\frac{9}{5}\big)\) = 32 Or, \(-\frac{4}{5}\) x ℉ = 32 ℉ = \(-\frac{-32\times5}{4}\) = -40 So, at – 40-degree temperature, both the Celsius and Fahrenheit scales read the same value.

At what temperature will both the Celsius and Fahrenheit scales read the same value?

Answer»

℉ = \(\frac{9}{5}\)(ºC) + 32

Or ℉ = \(\big(\)ºC x \(\frac{9}{5}\)\(\big)\)+ 32 t

℃ = (℉ - 32) x \(\frac{5}{9}\)

To find the temperature when both are equal, we use an old algebra trick and just set ℉ = ℃ and solve one of the equations.

℃ = \(\big(\)ºC x \(\frac{9}{5}\)\(\big)\)+ 32

Or, ℃ - \(\big(\)℃ x \(\frac{9}{5}\)\(\big)\) = 32

Or, \(-\frac{4}{5}\) x ℃ = 32

Or, ℃ = \(-\frac{32\times5}{4}\) = -40

℉ = \(\big(^oF\times\frac{9}{5}\big)\)+ 32

Or, ℉ - \(\big(^oF\times\frac{9}{5}\big)\) = 32

Or, \(-\frac{4}{5}\) x ℉ = 32

℉ = \(-\frac{-32\times5}{4}\) = -40

So, at – 40-degree temperature, both the Celsius and Fahrenheit scales read the same value.