InterviewSolution
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InterviewSolution
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At what temperature will He atoms have the same r.m.s. speed as `H_(2)` molecules have at `27^(@)C`? |
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Answer» `U_(RMS) = sqrt((3RT)/(M))` `U_((H_(2))) = sqrt((3RT)/(2.0)) = sqrt((3R xx 300)/(2.0))` [Gram molecular mass of `H_(2) = 2.0 g mol^(-1)`] `U_((He)) = sqrt((3RT)/(4.0))` [Gram atomic mass of `He = 4.0 g "atom"^(-1)`] According to the available data : `U_((H_(2))) = U_((He)) :. sqrt((3R xx 300)/(2.0)) = sqrt((3RT)/(4.0))` Square both sides, `(3R xx 300)/(2.0) = (3RT)/(4.0)` or `T = 600 K` or `t = 600 - 273 = 327^(@)C` |
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