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InterviewSolution
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At what temperature will the average velocity of oxygen molecules be sufficient to escape from the earth. Given mass of oxygen molecule `= 5.34 xx 10^(-26) kg`. Boltzmann constant, `k = 1.38 xx 10^(-23) J "molecule"^(-1) K^(-1)`. Escape velocity of earth `= 11.0 km s^(-1)`. |
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Answer» Correct Answer - `1.56 xx 10^(5)K` Here, `T=?` For oxygen molecule to escape from the earth, average KE of molecule = Escape energy of molecule `3/2 kT = 1/2 m upsilon_(e)^(2)` `T = (m upsilon_(e)^(2))/(3k) = (5.34 xx 10^(-26)(11 xx 10^(3))^(2))/(3 xx 1.38 xx 10^(-23))` `=1.56 xx 10^(5)K` |
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