1.

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere ? (Given : Mass of oxygen molecule (m) = 2.76 xx 10^(-26) kg , Boltzmann's constant k_B = 1.38 xx 10^(-23) JK^(-1) )

Answer»

`1.254xx10^(4)K`
`2.508 xx10^(4)K`
`5.016 xx10^4K`
`8.360 xx10^4K`

Solution :`v_e = SQRT((3k_BT)/m)`
`:. v_e^2=(3k_BT)/m`
`:. T = (v_E^2)/(3k_B)`
`:. T = ((11.2xx10^3)^2 xx2.76 xx10^(-26))/(3xx1.38 xx 10^(-23))`
`:. T = 83.626 xx10^3`
`= 8.363 xx10^4 K`
`:. T ~~ 8.360 xx 10^4 K` (Approx)


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