1.

At what temperature will the `rms` velocity of `SO_(2)` be the same as that of `O_(2) at 303 K`?A. `606 K`B. `403 K`C. `273 K`D. `303 K`

Answer» Correct Answer - A
According to the kinetic molecular theory of gases , we have
`u_(rms) = sqrt(3RT)/(M)`
We are given
`(u_(rms))_(SO_(2) = (u_(rms))_(O_(2))`
`sqrt((T_(SO_(2)))/(M_(SO_(2)))) = sqrt((T_(O_(2)))/(M_(O_(2))))`
Squaring both sides , we get
`(T_(SO_(2)))/(M_(SO_(2))) = (T_(O_(2)))/(M_(O_(2)))`
`T_(SO_(2)) = (T_(O_(2)M_(SO_(2))))/(M_(O_(2)))`
`= ((303 K)(64 g mol^(-1)))/((32 g mol^(-1)))`
`= 606 K`


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