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At what temperature will the `rms` velocity of `SO_(2)` be the same as that of `O_(2) at 303 K`?A. `606 K`B. `403 K`C. `273 K`D. `303 K` |
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Answer» Correct Answer - A According to the kinetic molecular theory of gases , we have `u_(rms) = sqrt(3RT)/(M)` We are given `(u_(rms))_(SO_(2) = (u_(rms))_(O_(2))` `sqrt((T_(SO_(2)))/(M_(SO_(2)))) = sqrt((T_(O_(2)))/(M_(O_(2))))` Squaring both sides , we get `(T_(SO_(2)))/(M_(SO_(2))) = (T_(O_(2)))/(M_(O_(2)))` `T_(SO_(2)) = (T_(O_(2)M_(SO_(2))))/(M_(O_(2)))` `= ((303 K)(64 g mol^(-1)))/((32 g mol^(-1)))` `= 606 K` |
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