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At what temperature would `CO_(2)` molecule have an rms speed equal to `H_(2)` at `27^(@) C`.A. `4400 K`B. `2200 K`C. `6600K`D. `1100 K`

Answer» Correct Answer - C
`rms_(CO_(2)) = rms_(H_(2))`
`(sqrt((3RT)/(M)))_(CO_(2)) = (sqrt((3RT)/(M)))_(H_(2))`
`(3 xx R xx T)/(44) = (3 xx R xx 300)/(2)`
`T = 6600 K`


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