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At What velocity does water emerge from an orifice in a tank in which gauge pressure is `3 xx 10^(5) Nm^(-2)` before the flow starts ? (Take the density of water `=1000 kg m^(-3)`.)A. `24.5 m s^(-1)`B. `14.5 m s^(-1)`C. `34.5 m s^(-1)`D. `44.5 m s^(-1)` |
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Answer» Correct Answer - A Here, `P=3xx10^(5) Nm^(-2), rho=1000 kgm^(-3), g=9.8 ms^(-2)` As `P=hrhog` `therefore h=(P)/(rhog)=(3xx10^(5))/(1000xx9.8)m` Velocity of efflux, `v=sqrt(2gh)=sqrt((2xx9.8xx3xx10^(5))/(1000xx9.8))` `=sqrt(600)=24.495 ms^(-1)~~24.5 ms^(-1)` |
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