At whattemperature the volume of 28 grams of N_2 will be 1L exerting a

1.	At whattemperature the volume of 28 grams of N_2 will be 1L exerting a pressure of1 atm?
Answer» SOLUTION :28g of `N_2` at 273K, 1 ATM pressure occupies 22.4L Charles. law is given as,` (V_1)/(V_2) = (T_1)/(T_2)` `V_1= 22.4L"" T_1= 273K` ` V_2= 1.0L"" T_2 =?` The temperature at which 1L of 28g of N, exerts a pressure of 1 atm =` T_2= (V_2T_1)/(V_1) = ( 1 XX 273 )/( 22.4) = 12.2 K=- 260.8^@ C `

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