AT673 K. in the formation of NH_(3) From N_(2) and H_(2) ,the partial pressures of N_(2) , H_(2) andand NH_(3)at equilibrium are 0.5 , 1 and 9 xx 10^(-3)atm respectively. (N_(2) + 3H_(2) hArr + Q) Calculate K_(c)for the reaction.

AT673 K. in the formation of NH_(3) From N_(2) and H_(2) ,the partial

1.	AT673 K. in the formation of NH_(3) From N_(2) and H_(2) ,the partial pressures of N_(2) , H_(2) andand NH_(3)at equilibrium are 0.5 , 1 and 9 xx 10^(-3)atm respectively. (N_(2) + 3H_(2) hArr + Q) Calculate K_(c)for the reaction.
Answer» 0.1 0.2 0.4 0.5 Solution :`N_(2)+3H_(2) harr 2NH_(3)` `K_(P)=(PN^(2)H_(3))/(PN_(2).PH_(2)^(3))=((9 xx 10^(-3))^(2))/(0.5 xx 1)=2 xx 81 xx 10^(-6)` `K_(P)=K_(c)(RT)^(Delta n), K_(c)=(2 xx 81 xx 10^(-6))/((0.0821 xx 673)^(-2))=0.5`