atan(4*x) %2B atan(6*x)=pi/4 – InterviewSolution

InterviewSolution

1.	atan(4x) %2B atan(6x)=pi/4
Answer» tan^-1A+tan^-1B=tan^-1(A+B/1-AB)hencetan^-1(4x+6x/1-24x^2)=tan^-1(1) as tanπ/4=1hence10x/1-24x^2=110x=1-24x^224x^2+10x-1=0hencex=-10+-√100+96/48x=-10+-√196/48x=-10+-14/48hencex=-10+14/48=4/48=1/12andx=-10-14/48=-24/48=-1/2

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