atan(a/b) - atan((a - b)/(a %2B b))=pi/4

1.	atan(a/b) - atan((a - b)/(a %2B b))=pi/4
Answer» tan^-1a-tan^-1b=tan^-1(a-b/1+ab)hencetan^-1(a/b-(a-b/a+b)/1+a/b(a-b/a+b)=tan^-1(a^2+ab-ab+b^2/a+b)/1+a^2-ab/ab+b^2)=tan^-1(a^2+b^2/a+b)/(a^2+b^2)/b(a+b))=tan^-1(1)=π/4 it is the answer above in the picture yes but how this step occurs

Answer»

tan^-1a-tan^-1b=tan^-1(a-b/1+ab)hencetan^-1(a/b-(a-b/a+b)/1+a/b(a-b/a+b)=tan^-1(a^2+ab-ab+b^2/a+b)/1+a^2-ab/ab+b^2)=tan^-1(a^2+b^2/a+b)/(a^2+b^2)/b(a+b))=tan^-1(1)=π/4

it is the answer above in the picture

yes

but how this step occurs

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atan(a/b) - atan((a - b)/(a %2B b))=pi/4

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