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(ataulate the mole fraction of 68% HNO³ solution |
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Answer» Answer: Let us consider that there is 100 grams of HNO 3
solution. ∴ Mass of HNO 3
+ Mass of H
O=100 g ∵ Mass of HNO 3
=12.2 g ∴12.2g+ Mass of H 2
O=100 g ∴ Mass of H 2
O=100−12.2=87.8 g n H 2
O
= M H 2
O
W H 2
O
= 18 87.8
=4.87 mol Number of moles of HNO 3
n HNO 3
= M HNO 3
W HNO 3
= 63 12.2
=0.1936 mol ∴ Total moles in the solution, n H 2
O
+n HNO 3
=4.87+0.1936=5.06 mol ∴ MOLE fraction of HNO 3
= Total number of moles (in soln.) No. of moles of HNO 3
= 5.06 0.1936
=0.0383 Now, MOLALITY of HNO 3
= Mass of solvent in gram Moles of solute (HNO 3
)
×1000 = 87.8 0.1936×1000
=2.205 mol kg −1
Hence, mole fraction and molality of HNO 3
, in a solution containing 12.2% HNO 3
is 0.0389 and 2.205 mol kg −1 respectively Explanation: hope this helps u plz mark me as brainlist |
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