1.

Atom of element B forms hcp lattice and those of the element A occupy 2/3 rd of tetrahedral void .what would be the formula of the compound ?

Answer»

Suppose number of atom B in hcp = N

No. of Tetrahedral void = 2N

Atom A occupying tetrahedral void = 2/3* 2N

Ratio   A:B   A4B3



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