1.

Atomic number of Ag is 47. in the same group, the atomic number of elements placed above and below Ag will be:A. 37,67B. 29,79C. 39,69D. 18,28

Answer» Correct Answer - B
`Cu rArr 47 - 18 = 29: Au rArr 47+32 =79`


Discussion

No Comment Found

Related InterviewSolutions