Atomic number of an element is 37. The valu e of (n + l) for the orbital from which the electron is removed to form +1 ion of its is

Atomic number of an element is 37. The valu e of (n + l) for the orb

1.	Atomic number of an element is 37. The valu e of (n + l) for the orbital from which the electron is removed to form +1 ion of its is
Answer» 5Explanation:The Electronic Configuration of RUBIDIUM(Atomic no:37) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 5s^1so the one electron should be removed from outermost shell( 5s^1) the value of (n+L) for this is= 5+0=0As value of l for s orbital is 0.