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Atomic numbers of `Cr` and `Fe` are respectively `24` and `26`. Which of the following is paramagnetic with the spin of the electron?A. `[Cr(CO)_(6)]`B. `[Fe(CO)_(5)]`C. `[Fe(CN)_(6)]^(4-)`D. `[Cr(NH_(3))_(6)]^(3+)` |
Answer» Correct Answer - D `[Cr(CO)_(6)] implies Cr^(0) (3d^(5) 4s^(2))` Since CO is a strong field ligand, there is resuffle of electron configuration resulting in zero unpaired electrons. `[Fe(CO)_(5)] implies Fe^(0)(3d^(6) 4s^(2))` Since CO is a strong field ligand, there is resuffle electron configuration resulting in zero inpaired electron resulting in zero unpaired electrons. `[Fe(CN)_(6)]^(4-) implies Fe^(2+) (3d^(6))` Since `CN^(-)` is a strong field ligand, there is resulffle of electron configurration resulting in zero unpaired electrons `[Cr(NH_(3))_(6)]^(3+) implies Cr^(3+) (3d^(3))` Than is no resutfle of electron configuration as enough d orbitals are vacant for `d^(2) sp^(3)` hybridization. Thus, there arer 3 unpaired electrons. |
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