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InterviewSolution
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Atoms of element B form hcp lattic and those of the element A occupy 2/3 of tetrahedral voids. What is the formuala fo the compound formed by these elements A and B ? |
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Answer» Suppose number of atoms B in hcp lattic = n As number of tetrahedral voids is double the number of atoms in the close packing . Therefore, number of tetrachedral voids = 2n. As atoms A occupy 2/3rd of the tetrahedral voids, therefore, number of atoms A in the lattic `= 2/3 xx 2n = ( 4n) /3` Ratio of A : B = `(4n)/2 : n = 4/3 : 1= 4:3 ` Hence, the formula of the compound ` A_(4)B_(3) ` |
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