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ATV tower has a height of 100m. How much population is covered by TV broadcast. If the average population density around the tower is `1000 km^(-2)` ? (radius of earth =`6.4xx10^(6)m`) |
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Answer» `h=100m, R=6.37xx10^(6)`, Average population density `=1000km^(-2)=1000(10^(3))^(-2)m^(-2)=10^(-3)m^(-2)` Distance up to which the transmissionn could be viewed `d=sqrt(2hR)` Total area over which transmisiion could be viewed `pi^(2)=2pihR` Population covered `=10^(-3)xx2pihR=10^(-3)xx2xx3.14xx100xx6.37xx10^(6)=40` lakh |
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