Average runs scored by Virat Kohli after his 10th innings is 45. Highe

1.	Average runs scored by Virat Kohli after his 10th innings is 45. Highest score is 100 runs more than his lowest score. Had he scored average of his highest and lowest score in his 11th innings, the average score after 11th innings would increase by 4 runs. Find his lowest score1. 402. 393. 454. 30
Answer» Correct Answer - Option 2 : 39 Given: Average after 10^th innings = 45 Highest score – lowest score = 100 New average = 45 + 4 = 49 Score of 11^th innings = (Highest score + lowest score)/2 Formula used: Average = Total sum/Total number Total sum = Average × Total number Calculation: Total score after 10 innings = 45 × 10 = 450 Let, lowest score = l and highest score = h Score of 8 innings + l + h = 450 ---- (1) New average = 49 Total score after 11 innings = 49 × 11 = 539 Score of 11^th inning = (l + h)/2 Score of 8 innings + (l + h) + (l + h)/2 = 539 ---- (2) Now, eqn. (2) – (1) ⇒ (l + h)/2 = 539 – 450 = 89 ⇒ l + h = 89 × 2 = 178 ---- (a) ⇒ h – l = 100 ---- (b) Solving eqn. (a) and (b) h = 139 and l = 39 ∴ The lowest score is 39.

Average runs scored by Virat Kohli after his 10th innings is 45. Highest score is 100 runs more than his lowest score. Had he scored average of his highest and lowest score in his 11th innings, the average score after 11th innings would increase by 4 runs. Find his lowest score1. 402. 393. 454. 30

Answer» Correct Answer - Option 2 : 39

Given:

Average after 10^th innings = 45

Highest score – lowest score = 100

New average = 45 + 4 = 49

Score of 11^th innings = (Highest score + lowest score)/2

Formula used:

Average = Total sum/Total number

Total sum = Average × Total number

Calculation:

Total score after 10 innings = 45 × 10 = 450

Let, lowest score = l and highest score = h

Score of 8 innings + l + h = 450 ---- (1)

New average = 49

Total score after 11 innings = 49 × 11 = 539

Score of 11^th inning = (l + h)/2

Score of 8 innings + (l + h) + (l + h)/2 = 539 ---- (2)

Now, eqn. (2) – (1)

⇒ (l + h)/2 = 539 – 450 = 89

⇒ l + h = 89 × 2 = 178 ---- (a)

⇒ h – l = 100 ---- (b)

Solving eqn. (a) and (b)

h = 139 and l = 39

∴ The lowest score is 39.