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ax + by = 5,ax2 + by2 = 10,ax3 + by3 = 50,ax4 + by4 = 130,13 (x + y - xy) - 120(a + b) = ? |
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Answer» ax + by = 5---(1) ax2 + by2 = 10---(2) ax3 + by3 = 50---(3) ax4 + by4 = 130---(4) From (2), ax2 + by2 = 10 ⇒ (ax2 + by2) (x + y) = 10(x + y) ⇒ ax3 + by3 + ax2y + bxy2 = 10(x + y) ⇒ 50 + xy(ax + by) = 10(x + y) (From (3)) ⇒ 50 + 5xy = 10(x + y)---(5) From (1) From (3), ax2 + by3 = 50 ⇒ (ax3 + by3)(x + y) = 50 (x + y) ⇒ 130 + (ax2 + by2)xy = 50 (x + y) From (4) ⇒ 130 + 10xy = 50(x + y)----(6) Now, (6) - 2 x (5), we get 130 + 10xy - (100 + 10xy) = 50(x + y) - 20(x + y) ⇒ 130 - 100 = 30(x + y) ⇒ x + y = 30/30 = 1 ⇒ x + y = 1 Put x + y = 1 in equation (5) we get 50 + 5xy = 10 ⇒ 5xy = 10 - 50 = -40 ⇒ xy = -40/5 = -8 From (1), ax + by = 5 ⇒ (ax + by)(x + y) = 5(x + y) ⇒ ax2 + by2 + axy + bxy = 5 (\(\because\) x + y = 1) ⇒ 10 + xy (a + b) = 5 (From (2)) ⇒ 10 - 8(a + b) = 5 (\(\because\) xy = -8) ⇒ a + b = \(\frac{5-10}{-8}\) = \(\frac{-5}{-8}\) = \(\frac58\) Now, 13 (x + y - xy) - 120(a + b) = 13(1 - (-8)) -120 x \(\frac58\) = 13 x 9 - 15 x 5 = 117 - 75 = 42 |
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