1.

B)1)Solve following subquestions.The roots of quadratic equation2x2-6x+K=0 are real and equal, find K.

Answer»

2x^2-6x+k=0; b^2-4ac = (-6)^2-4(2)(k); 36-8k=0; 36=8k ; k=36/8=4.5

condition for real and equal root b^2-4ac=0(-6)^2-4(2)(k)=036-8k=08k= 36k= 36/8= 9/2

2x^2-6x+k, formula b^2-4ac ; (-6)^2-4(2)(k); 36 = 8k; k= 36 / 8 = 4.5



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