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B-13. The equation of the diameter of the circle (2+(y+ 1) 16 which bisects the chord cut off by thecircle on the line x - 2y-3 0 is(A)x+ 2y 0(B) 2x+ y-3 0 (C) 3x + 2y-4(D) 3x-2y-4 o |
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Answer» The diameter must pass through center of circle (2,-1)Also, it bisects the chord cut off from line x-2y-3=0. So, diameter must be perpendicular to this line. So, slope must be -2.So, let equation of diameter be y=mx+c Here, m=-2so, y=-2x+cIt passes through (2,-1)So, -1=-4+c which gives c=3So, equation is : y+2x-3=0 |
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