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B 2 मा .बए ... 0७४० ७ का, 1, 2. elकि. |
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Answer» a=8,d=10-8=2 60th term=a+(60-1)d=8+(59)2=8+118=126 AP:8,10,12.....120,122,124,126 To find sum of last ten terms, reverse the order of AP 126,124,122,120,.....,12,10,8 Now we have to find sum of first ten terms=(n/2)[2a+(n-1)d]=5[2*126+(10-1)(-2)]=5[252-18]=5(134) =670 |
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