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b^(-4)/(2/5)^(-8)=(2/5)^(2*x) |
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Answer» (2/5)^-4 ÷ (2/5)^-8 = (2/5)^2x (2/5)^[-4 - (-8)] = (2/5)^2x (2/5)^4 = (2/5)^2x 2x = 4 x = 4/2 x = 2 (2/5)^-4-(-8)=(2/5)^2x=(2/5)^-4+8=(2/5)^2x=(2/5)^4=(2/5)^2x=4 = 2x(as bases are same so the powers too will be same(=X =4/2= X =2 |
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