B gives red colouration with `FeCl_(3)`.A. ` A " is " CH_(3)-underset(CH_(3))underset(|)(CH)-overset(O)overset(||)(C)-OH`B. ` D " is " CH_(3)-underset(CH_(3))underset(|)(CH)-NH_(2)`C. ` D " is " CH_(3)-underset(CH_(3))underset(|)(CH)-OH`D. Both A and C

B gives red colouration with `FeCl_(3)`.A. ` A " is " CH_(3)-underset

1.	B gives red colouration with `FeCl_(3)`.A. ` A " is " CH_(3)-underset(CH_(3))underset(\|)(CH)-overset(O)overset(\|\|)(C)-OH`B. ` D " is " CH_(3)-underset(CH_(3))underset(\|)(CH)-NH_(2)`C. ` D " is " CH_(3)-underset(CH_(3))underset(\|)(CH)-OH`D. Both A and C
Answer» Correct Answer - B

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B gives red colouration with `FeCl_(3)`.A. ` A " is " CH_(3)-underset(CH_(3))underset(|)(CH)-overset(O)overset(||)(C)-OH`B. ` D " is " CH_(3)-underset(CH_(3))underset(|)(CH)-NH_(2)`C. ` D " is " CH_(3)-underset(CH_(3))underset(|)(CH)-OH`D. Both A and C

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