InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
b) Sum of the present ages of two friends are 23 years, five years ago productof their ages was 42. Find their ages 5 years hence. |
|
Answer» Let present of first friend be xThen, present age of second friend = 23 - x Five years ago:First friend age = x - 5Second friend age= 23 - x - 5= 18 - x As per given condition (x - 5)(18 - x) = 4218x - x^2 - 90 + 5x = 42x^2 - 23x + 132 = 0x^2 - 12x - 11x + 132 = 0x(x - 12) - 11(x - 12) = 0(x - 11)(x - 12) = 0x = 11, 12 After 5 years there ages are16 years and 17 years |
|