1.

(b.)what will be the loss in mass when 42g of magnesium carbonate is strongly heated to give magnesium oxide ?​

Answer»

MgCO 3 →MgO+CO 2 Molecular WEIGHT of MgCO 3 = 24 + 12 +16 x 3 = 84Molecular weight of MgO= 24 + 16 = 40On HEATING 84 gms of MgCO 3 the quantity of MgO obtained= 40 gms∴ On heating 5 gms of MgCO 3 the quantity of MgO obtained= 8440 X5gms= 2.38 gmsExplanation:......Hope it helps you ‼️



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