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Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from Bag II. |
Answer» A= taking red ball B=selecting a Ball `P(B_1)=P(B_2)=1/2` `P(A/B_1)=3/7` and `P(A/B_2)=5/11` `P(B_2/A)=(P(A/B_2)P(B_2))/(P(A/B_2)P(B_2)+P(A/B_1)P(B_1))` `P(B_2/A)=((5/11)(1/2))/((5/11)(1/2)+(3/7)(1/2))` =`35/68`. |
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