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Balance by oxidation number method: Mg + HNO_(3) rarr Mg(NO_(3))_(2) + NO_(2) + H_(2)O. |
Answer» Solution : Step 1 Step 2. `MG + 2HNO_(3) rarr Mg(NO_(3))_(2) + NO_(2) + H_(2)O` Step 3. To balance the number of OXYGEN atoms and HYDROGEN atoms `2HNO_(3)` is multiplied by 2 Mg + `4HNO_(3) rarr Mg(NO_(3))_(2)+2NO_(2_ + H_(2)O` Step 4. To balance the number of hydrogen atoms, the `H_(2)O` MOLECULE is multiplied by 2 Mg + `4HNO_(3) — Mg(NO_(3))_(2) + 2NO_(2) + 2H_(2)O` |
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