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Balance by oxidation number method: Mg+HNO_(3)toMg(NO_(3))_(2)+NO_(2)+H_(2)O. |
Answer» SOLUTION :![]() Step 2. `Mg+2HNO_(3)toMg(NO_(3))O_(2)+NO_(2)+H_(2)O` Step 3. To balance the NUMBER of oxygen ATOMS and hydrogen atoms `2HNO_(3)` is MULTIPLIED by, `Mg+4HNO_(3)toMg(NO_(3))_(2)+2NO_(2)+H_(2)O` Step 4. To balance the number of hydrogen atoms, the H,O MOLECULE is multiplied by 2. `Mg+4HNO_(3)toMg(NO_(3))_(2)+2NO_(2)+2H_(2)O` |
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