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Balance the equation by oxidation number method Mg+HNO_(3) to Mg(NO_(3))_(2)+N_(2)O+H_(2)O |
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Answer» SOLUTION :STEP -1,2 `M overset(0)(g)+H overset(+5)(N) O_(3) to M overset(+2) (g) (overset(+5)(g) O_(3))_(2) +N_(2)^(+1) O+H_(2)O` Step -3  Step -4 Mg equation is multipled by 4 and `HNO_(3)` equation is multiplied by 2. Now, `4Mg+2HNO_(3) to 4Mg(NO_(3))_(2)+N_(2)O+H_(2)O` Step -5: Balance all atoms other than O and H. `4Mg+10HNO_(3) to 4Mg(NO_(3))_(2)+N_(2)O+H_(2)O` Step -6 : Balance H and O by adding `H_(2)O` MOLECULES. `4Mg+10HNO_(3) to 4Mg(NO_(3))_(2)+N_(2)O+5H_(2)O` |
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