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Balance the following by ion electron method is basic medium. `NO_(3)^(ө)+Znrarr Zn^(2+)+NH_(4)^(oplus)`. |
Answer» Two half reactions are a. `NO_(3)^(ө)rarrNH_(4)^(o+)` b.`ZnrarrZn^(2+)` First balance `O` atoms in basic medium. a. `NO_(3)^(ө)+3H_(2)OrarrNH_(4)^(o+)+6overset(ө)OH` Balancing `H` atoms in basic medium `NO_(3)^(ө)+3H_(2)+4H_(2)OrarrNH_(4)^(o+)+6overset(ө)OH+4overset(ө)OH` Balancing the charge: `NO_(3)^(ө)+8e^(-)+7H_(2)OrarrNH_(4)^(o+)+10overset(ө)OH` b. `ZnrarrZn^(2+)+2e^(-)` Now reaction is `4Zn+NO_(3)^(ө)+7H_(2)Orarr4Zn^(2+)+NH_(4)^(o+)+10overset(ө)OH` |
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