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Balance the following equation by ion electron method (i) FeCI_(3)+H_(2)SrarrFeCI_(2)+HCI+S (ii) Cu+HNO_(3)rarrCu(NO_(3))_(2)+NO+H_(2)O (iii)KI+CI_(2)rarrKCI+I_(2) (iv) MnO_(2)+HCIrarrMnCI_(2)+H_(2)O+CI (iv) H_(2)S+HNO_(3)rarrH_(2)SO_(4)+NO_(2)+N_(2)O |
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Answer» (ii) `3Cu+8HNO_(3)rarr3Cu(NO_(3))_(2)+2NO+4H_(2)O` (iii)`2KI+CI_(2)rarr2KCI+I_(2)` `MnO_(2)+4HCI rarr MnCI rarr MnCI_(2)+CI_(2)+2H_(2)O` (v)`H_(2S+8HNO_(3))rarrH_(2)SO_(4)+8NO_(2)+4H_(2)O` |
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