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Balance the following equation by oxidation number methodCu + HNO_(3) to Cu(NO_(3))_(2)+NO_(2) +H_(2) O |
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Answer» SOLUTION :`CU+HNO_(3) to Cu (NO_(3))_(2) + NO_(2)+H_(2)O` `Coverset (0) underset(2e^(-))underset(darr)(u)+Hoverset(+ 5)underset(IE)underset(UARR)(N)0_(3)rarrCoverset(+2)(u)(No_(3))_(2)+overset(+4)(N)0_(2)+H_(2)0` `Cu+ 2HNO_(3) to cu(NO_(3))_(2) + NO_(2)+H_(2)O` `Cu+2HNO_(3) +2HNO_(3) to Cu(NO_(3))_(2) +2NO_(2) + 2H_(2)O` `Cu+ 4 HNO_(3) to Cu(NO_(3))_(2) + 2NO_(2) + 2H_(2) O` |
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