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Balance the following equation by oxidation number method.KMNO_(4)+HClrarrKCl+MnCl_(2)+H_(2)O+Cl_(2) |
Answer» SOLUTION : (ii) `2KMnO_(4)` + 10HC1 `rarr` KCl + `MnCl_(2) + H_(2)O + Cl_(2)` (iii) Balance the equation atomically (except O and H). `2KMnO_(4) `+ 10HCl `rarr`2KCl + `2MnCl_(2) + H_(2)O + Cl_(2)` (iv) Balance chlorine atoms by ADDING HCl and MULTIPLYING `Cl_(2)` by 5. `2KMnO_(4)` + 16HCl to 2KCl + `2MnCl_(2) + H_(2)O + 5Cl_(2)` (v) To balance O and H, `H_(2)O` is MULTIPLIED by 8. `2KMnO_(4)` + 16HCl rarr 2KCl + `2MnCl_(2) + 8H_(2)O + 5Cl_(2)` . |
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