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Balance the following equation in basic medium by both oxidation number and ion electron method identify the reducatants and the oxidants (i) P_(4)NaOH+H_(2)O to PH_(3)+3NaH_(2)PO_(2) (ii)N_(2)H_(4)(g)+CIO_(3)^(-)(Aq) to NO(g)+CI^(-)(aq) (iii)CI_(2)O_(7)(g)+H_(2)O_(2)(aq) to CIO_(2)^(-)(aq)+O_(2)(g) (iv) Cr(OH)_(4)^(-)(aq)+H_(2)O(aq)to H_(2)O_(2)(aq) to CrO_(4)^(2-)(aq)+H_(2)O(l) (v)Zn(s)+NO_(3)^(-)(aq) to Zn^(2+)(aq)+NH_(4)^(+)(aq) (vi)AI(s)+NO_(3)^(-)(aq) to AI(OH)_(4)^(-)(aq)+NH_(3)(g) (vii)PbO_(2)(s)+CI^(-)(aq) to Pb(OH)_(3)^(-)(aq)+CIO^(-)(aq) viii)Fe(OH)_(3)(aq)+H_(2)O_(2)to Bi(s)+SnO_(3)^(2-)(aq) (ix) Bi(OH)_(3)(s)+SnO_(21)^(2-)(aq) to Bi(s)+SnO_(3)^(2-)(aq) (x)Cr (S)+CIO_(4)^(-)(aq) to Cr(OH)_(3)(s)+CIO_(3)(aq) |
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Answer» Solution :(i)`P_(4)(s)+3NaOH(AQ)+3H_(2)O(l)rarrPH_(3)(g)+3 NaH_(2)PO_(2)(aq)` (ii)` 3N_(2)H_(4)(g)+4CIO_(3)^(-)(aq)rarr6NO(g)+4CI^(-)(aq)+6H_(2)O(l)` (iii)`CI_(2)O_(7)(g)+4H_(2)O_(2)(aq)+3H_(2)O_(2)(aq)rarr2CI_(2)^(-)(aq)+4O_(2)(g)+5H_(2)O(l)` (iv)`2cr(OH)_(4)^(-)(aq)+2OH^(-)(aq)+3H_(2)O_(2)(aq)rarr2CrO_(4)^(-)(aq)+4 O_(2)(g)+5H_(2)O` `(v)4Zn(s)+3NO_(3)^(3)(aq)+7H_(2)O(l)rarr4Zn^(2+)(aq)+NH_(4)^(+)(aq)+10 OH^(-)(aq)` (vii)`PbO_(2)(s)+CI^(-)(aq)+H_(2)O(l)+OH^(+)(aq)rarr8AI(OH)_(4)^(-)(aq)+3NH+(3)(g)` (VIII)`2BI(OH)_(3)(s)3SnO_(2)^(-)(aq)rarr2Bi(s)+3SnO_(3)^(2-)(aq)+3H_(2)O(l)` (ix)`2Bi(OH)_(3)(s)+3SnO_(2)^(2-)(aq)rarr2Bi(s)+3SnO_(3)^(2-)(aq)+3H_(2)O(l)` (x)`2Cr(s)+3CIO_(4)^(-)(aq)+3H_(2)Orarr2Cr(OH)_(3)(s)+3CIO_(3)^(-)(aq)` |
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