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Balance the following equation using oxidation number methodAs_(2)S_(3)+HNO_(3)+H_(2)O rarr H_(3)AsO_(4)+H_(2)SO_(4)+NO |
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Answer» Solution : `As_(2)S_(3)+HNO_(3)+H_(2)OrarrH_(3)AsO_(4)+H_(2)SO_(4)+NO` `overset(+3)(As_(2)S_(3))+overset(+5)(HNO_(3))+H_(2)O RARR overset(+5)(H_(3)AsO_(4))+H_(2)SO_(4)+overset(+2)(NO)`  `As_(2)S_(3)rarrH_(3)AsO_(4)+2e^(-)xx3` `HNO_(3)+3e^(-)rarrNOxx2` `3As_(2)S_(3)rarr 3H_(3)AsO_(4)+cancel(6e^(-))` `3As_(2)S_(3)+2HNO_(3)rarr6H_(3)AsO_(4)+2NO` To balance oxygen and SULPHUR, `H_(2)O` and `H_(2)SO_(4)`are added. `3As_(2 S_(3) + 2HNO_(3)+H_(2)O rarr 6H_(3)AsO_(4)+2NO+H_(2)SO_(4)` `3As_(2)S_(3)+28HNO_(3)+4H_(2)O rarr 6H_(3)AsO_(4)+28NO+9H_(2)SO_(4)` |
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