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| 1. |
Balance the following equations by oxidation number method. KMnO_(4)+H_(3)AsO_(3)+HCl toKCl+MnCl_(2)+H_(3)AsO_(4)+H_(2)O |
| Answer» Solution :`3 xx 55.85 g , 3 xx 6.022 xx 10^(23) "atoms"(3FE) + UNDERSET("4 moles" 4 xx 18.016 g 4 xx 6.022 xx 10^(23) "MOLECULES")(4H_(2)O) to underset("one MOLE" 231.55 g, 6.022 xx 10^(23) "molecules")(Fe_(3)O_(4)) + underset("4 moles" 4 xx 22.4 L "at S.T.P.") (4 xx 6.022 xx 10^(23) "molecules")` | |