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Balance the following equations by the oxidation number method. (a) Fe^(+2)+H^(+)+Cr_(2)O_(7)^(-2)toCr^(+3)+Fe^(+3)+H_(2)O (b) I_(2)+NO_(3)^(-)toNO_(2)+IO_(3)^(-) ( c) I_(2)+S_(2)O_(3)^(-2)toI^(-)+S_(4)O_(6)^(-2) (d) MnO_(2)+C_(2)O_(4)^(-2)toMn^(+2)+CO_(2) |
Answer» Solution :(a)  Balance by oxidation number. `6Fe^(+2)+H^(+)+Cr_(2)O_(7)^(-2)to2Cr^(+3)+6Fe^(+3)+H_(2)O` Balance charges. `6Fe^(+2)+14H^(+)+Cr_(2)O_(7)^(-2)to2Cr^(+3)+6Fe^(+3)+H_(2)O` Balance O and H. `6Fe^(+2)+14H^(+)+Cr_(2)O_(7)^(-2)to2Cr^(+3)+6Fe^(+3)+7H_(2)O` (B) `I_(2)+NO_(3)^(-)toNO_(2)+IO_(3)^(-)`  Balance by oxidation no. `I_(2)+10NO_(3)^(-)to10NO_(2)+2IO_(3)^(-)` Balance charges. `I_(2)+10NO_(3)^(-)+8H^(+)to10NO_(2)+2IO_(3)^(-)` Balance H and O. `I_(2)+10NO_(3)^(-)+8H^(+)to10NO_(2)+2IO_(3)^(-)+4H_(2)O` ( c) `I_(2)+S_(2)O_(3)^(-2)toI^(-)+S_(4)O_(6)^(-2)`  `I_(2)+2S_(2)O_(3)^(-2)to2I^(-)+S_(4)O_(6)^(-2)` (d) `MnO_(2)+C_(2)O_(4)^(-2)toMn^(+2)+CO_(2)`  `MnO_(2)+C_(2)O_(4)^(-2)+4H^(+)toMn^(+2)+2CO_(2)` `MnO_(2)+C_(2)O_(4)^(-2)+4H^(+)toMn^(+2)+2CO_(2)+2H_(2)O` |
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