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Balance the following equations by using oxidation number method. K_(2)Cr_(2)O_(7)+KI +H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+I_(2)+H_(2)O |
Answer» SOLUTION :`K_(2)Cr_(2)O_(7)+KI +H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+I_(2)+H_(2)O`  Step 2.`K_(2)Cr_(2)O_(7)+6KI +H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3I_(2)+H_(2)O` Step 3. To balance other atoms `K_(2)Cr_(2)O_(7)+6KI +H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3I_(2)+H_(2)O` Step 4. To balance oxygen and hydrogen, `H_(2)O` and `H_(2)SO_(4)` are multiplied by 7 `K_(2)Cr_(2)O_(7)+6KI +7H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3I_(2)+H_(2)O` |
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